It was the first international match in South Africa after the break due to the Corona virus epidemic. Johnny Bairstow scored an unbeaten 86 off 48 balls to give England victory in the first T20 match against South Africa.
Jonny Bairstow scored an unbeaten 86 off 48 balls to help England win by 5 wickets in the first T20 International match against South Africa. South Africa had scored 179 runs for 6 wickets, in response to which England scored 183 runs for 5 wickets with 4 balls left. Bairstow hit the first and second ball of the last over with fours and sixes respectively to lead the team to victory.
It was the first international match in South Africa after the break due to the Corona virus epidemic. England won this match played in Cape Town and got a 1-0 lead in the three-match series. The next match will be played on 29 November.
South Africa dominated the match, but Bairstow Hendrix’s Bairstow and captain Eoin Morgan scored 28 runs in the 17th over. The match map changed with this over. England needed 51 runs from 24 balls before this over, but after this 23 runs were needed from 18 balls.
Morgan sat in mid-wicket off Lungi Nagidi in the next over. Despite this, Bairstow played the role of finisher, maintaining restraint. He hit 9 fours and 4 sixes in his innings. Earlier, in the bowling for England, Sam Curren took 3 wickets for 28 runs.