If you use a DataOutputStream, you can just dump data to it, and ti will be automatically converted to network byte-order for you.

Therefore, you can do:

DataOutputStream dos = new DataOutputStream();

dos.writeInt(09);

If you really want to do binary-coded decimal (which is what you are doing above), then you'll have to convert each number to a character representing your digit (i.e. convert 1 to "1") and then send those bytes as text.

I think that's more trouble that it's worth.

-chris

Are you saying that you want to work digit-by-digit, or do a straight decimal-to-hexadecimal conversion, in which case each byte will not be directly assignable to a digit in the decimal value? If the latter, you can do it without writing very little code by using the static method Integer.toHexString(int value) to give you a String representation of the hexadecimal value, following by application of the appropriate method in the Byte class to convert each character to a byte.