Hello,

I'm trying to keep things a little bit more on the Lexer before going to the parser, i have a small example that i cannot see it working and the theory says "it should work".

i'll post the exact code:

class STLexer extends Lexer;

options { k=4;}

TIME: "tA" | "tiB";

IDENTIFIER : ('a'..'z')+;

this code compiles ok, but if i change "tB" to "tiB", it gives me this error.

ANTLR Parser Generator Version 2.7.5 (20050128) 1989-2005 jGuru.com

ST.g: warning:lexical nondeterminism between rules TIME and IDENTIFIER upon

ST.g: k==1:'t'

ST.g: k==2:'i'

ST.g: k==3:

ST.g: k==4:

Now, i know i can do this easily on the parser, but is that the only way to do it? can't i return to the parser simply the token TIME.

Or to do this, i have to hardcode the match on "tiB"?

This should be simple... any help appreciated.

Jorge Pinto