Re: AlphaNumeric Sorting for the array of String
Posted By:
Bhagyashree_Jayaram
Posted On:
Monday, February 2, 2004 09:52 PM
Hi,
In this case you need to use a comparator and here is the code.
import java.util.Comparator;
import java.util.StringTokenizer;
public class MyComparator implements Comparator {
/* (non-Javadoc)
* @see java.util.Comparator#compare(java.lang.Object, java.lang.Object)
*/
public int compare(Object arg0, Object arg1) {
// TODO Auto-generated method stub
if ((arg1 instanceof String) && (arg0 instanceof String)){
if (((String)arg0).indexOf("Name_") !=-1 && ((String)arg1).indexOf("Name_") !=-1){
if (getNumber((String)arg0) == getNumber((String)arg1)){
return ((String)arg0).compareTo(((String)arg1));
}else if (getNumber((String)arg0) > getNumber((String)arg1))
return 1;
else
return -1;
}
}
return 0;
}
public int getNumber(String value){
StringTokenizer st = new StringTokenizer(value ,"0123456789");
String firstValue = st.nextToken();
String secondValue = st.nextToken();
int retValue =Integer.parseInt(value.substring(value.indexOf(firstValue) + firstValue.length(),value.indexOf(secondValue)));
return retValue;
}
}
and when you call sort pass as follows
Arrays.sort(colls,new MyComparator());
Hope this helps...
Bhagya
