Topic: How can i modify an entry in Microsoft Exchange 5.5

How can i modify an entry in Microsoft Exchange 5.5

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Posted By: Anonymous
Posted On: Thursday, October 24, 2002 02:16 AM

I'm making an interface between our database and our Microsoft Exchange 5.5. My objetive is to change the Exchange's data automatically. I'm new with jndi. I can read from the directory but when i go to modify any data, java returns me this exception: javax.naming.NameNotFoundException: [LDAP: error code 32 - No Such Object]; remaining name 'uid=EDUB, ou=my_site, o=my_organization' The uid, site, and organization are correct. What's happening? The program's code is the next one: try { Hashtable env = new Hashtable(); env.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory"); env.put(Context.PROVIDER_URL, "ldap://my_exch_serv:389&q More>>

I'm making an interface between our database and our Microsoft Exchange 5.5. My objetive is to change the Exchange's data automatically.

I'm new with jndi. I can read from the directory but when i go to modify any data, java returns me this exception:

javax.naming.NameNotFoundException: [LDAP: error code 32 - No Such Object]; remaining name 'uid=EDUB, ou=my_site, o=my_organization'

The uid, site, and organization are correct. What's happening?

The program's code is the next one:

			

			try {
			

			Hashtable env = new Hashtable();
			

			env.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory");
			

			env.put(Context.PROVIDER_URL, "ldap://my_exch_serv:389");
			

			

			String pClave= new String("uid=EDUB, ou=my_site, o=my_org");
			

			ModificationItem[] pMod= new ModificationItem[1];
			

			Attribute modTelefono = new BasicAttribute("telephonenumber", "945144098");
			

			pMod[0] = new ModificationItem(DirContext.REPLACE_ATTRIBUTE, modTelefono);
			

			

			

			DirContext ctx = new InitialDirContext(env);
			

			ctx.modifyAttributes(pClave, pMod);
			

			} catch (Exception e) {
			

			e.printStackTrace();
			

			}

Thank you very much in advance for your interest.

Greetings!!!

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Re: How can i modify an entry in Microsoft Exchange 5.5

Posted By: Anonymous
Posted On: Thursday, October 24, 2002 03:16 AM

This is an autoanswer.

I was wrong with Exchange's authentication. I had to autheticate at exchange server. I had to pass a user with administrator permissions. That was my principal error.

Other problem was the url that i was using to indentify the entry i would want to change. I am using "uid=user_name" but i had to use "cn=user_name, cn=Recipients".

Well, the correct code i am using in this moments is below:


    try {
      Hashtable env = new Hashtable();
      env.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory");
      env.put(Context.PROVIDER_URL, "ldap://my_exchange_server:389");
      env.put(Context.SECURITY_AUTHENTICATION, "simple");
      env.put(Context.SECURITY_PRINCIPAL, "cn=admon_username, ou=my_site, o=my_org");
      env.put(Context.SECURITY_CREDENTIALS, "admon_password");

String pClave= new String("cn=user_to_change, cn=Recipients, ou=my_site, o=my_org");
    ModificationItem[] pMod= new ModificationItem[1];
    Attribute modTelefono = new BasicAttribute("telephonenumber", "945144098");
    pMod[0] = new ModificationItem(DirContext.REPLACE_ATTRIBUTE, modTelefono);


      DirContext ctx = new InitialDirContext(env);
      ctx.modifyAttributes(pClave, pMod);
    } catch (Exception e) {
      e.printStackTrace();
    }

Hope this answer was usefull to someone else.

Greetings!!

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